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+//Chemical Engineering Thermodynamics
+//Chapter 14
+//Thermodynamics of Chemical Reactions
+
+//Example 14.15
+clear;
+clc;
+
+//Given
+//C3H8 = C3H6 + H2... (i)
+//C3H8 = C2H4 +CH4...(ii)
+Kp1 = 7.88;//Equilibrium constant of equation (i)
+Kp2 = 775;//Equilibrium constant of equation (ii)
+T = 760+273;//Temperature in K
+
+//To Calculate the equilibrium composition of the mixture
+//Basis: 1 mole of C3H8 in feed
+//From the equations (a) &(b) (page no 343); y/x = z (say)
+z = (Kp2/Kp1)^(1/2);
+//Substituting y = z*x in equation(a), we got the equation p:
+x = poly(0,'x')
+p = (1+Kp1+Kp1*(z^2)+2*Kp1)*x^2 - Kp1;
+q = roots(p);
+x = q(1);
+y = z*x;
+mprintf('Moles of H2, C3H6, C2H4 and CH4 formed at equilibrium are %f %f %f %f respectively.',x,x,y,y);
+//end \ No newline at end of file