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Diffstat (limited to '479/CH13/EX13.17')
-rwxr-xr-x | 479/CH13/EX13.17/Example_13_17.sce | 40 | ||||
-rwxr-xr-x | 479/CH13/EX13.17/Example_13_17.txt | 3 |
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diff --git a/479/CH13/EX13.17/Example_13_17.sce b/479/CH13/EX13.17/Example_13_17.sce new file mode 100755 index 000000000..02cb59dac --- /dev/null +++ b/479/CH13/EX13.17/Example_13_17.sce @@ -0,0 +1,40 @@ +//Chemical Engineering Thermodynamics
+//Chapter 13
+//Thermodynamics in Phase Equilibria
+
+//Example 13.17
+clear;
+clc;
+
+//Given
+H_ex = 539;//Heat of vapoization of water in Kcal/Kg
+Tc = 647;//Critical temperature in K
+Pc = 218;//Critical pressure in atm
+Tb = 373;//Boiling point of water in K
+t = 100;//temperature in deg cel
+M = 18;//Molecular weight of water
+P = 1;//pressure at boiling point in atm
+P1 = 1.033*10^4;//pressure in Kgf/sq m
+
+//To Calculate the heat of vapourisation of water by Vishwanath and Kuloor method and by Riedel's method and compare with the experimental value
+//(i) Using Vishwanath and Kuloor method
+H_c = (4.7*Tc*((1-(P/Pc))^0.69)*log(P/Pc))/((1-(Tc/Tb))*18);
+mprintf('(i)The heat of vapourisation of water using Vishwanath and Kuloor method is %f Kcal/Kg',H_c);
+D = (H_c-H_ex)*100/H_c;
+mprintf('\n The deviation occurs using this method is %f percent',D);
+
+//(ii)Using Riedel's method
+H_c = (Tb*2.17*(log(218)-1))/((0.93-(Tb/Tc))*18);
+mprintf('\n\n(ii)The heat of vapourisation of water using Riedel method is %f Kcal/Kg',H_c);
+D = (H_c-H_ex)*100/H_c;
+mprintf('\n The deviation occurs using this method is %f percent',D);
+
+//(iii)By using given vapour equation; logP = 8.2157-(2218.8537/(273.16+t)), t is in deg cel
+//From steam table,
+Vv = 1.673;//in cubic meter/Kg
+Vl = 0.001;//in cubic meter/Kg
+H_c = (2218.8/(273.16+t)^2)*(2.3*Tb*P1*(Vv-Vl)/427);
+mprintf('\n\n(iii)The heat of vapourisation using the given vapour equation is %f Kcal/Kg',H_c);
+D = (H_c-H_ex)*100/H_c;
+mprintf('\n The deviation occurs using this method is %f percent',D);
+//end
\ No newline at end of file diff --git a/479/CH13/EX13.17/Example_13_17.txt b/479/CH13/EX13.17/Example_13_17.txt new file mode 100755 index 000000000..59ddec64e --- /dev/null +++ b/479/CH13/EX13.17/Example_13_17.txt @@ -0,0 +1,3 @@ +For example 13.17(i), the answer given in the book, heat of vapourisation H_c = 532Kcal/Kg and the deviation as 1.3 %
+ but i am getting H_c = 1234.397 Kcal/Kg,using the Vishwanath and Kuloor method
+ and the deviation is 56.335 %.There might be some calculation mistake in the book.
\ No newline at end of file |