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+//Chemical Engineering Thermodynamics
+//Chapter 12
+//Refrigeration
+
+//Example 12.3
+clear;
+clc;
+
+//Given
+//Consider the figure 12.4 (page no 226) 
+m = 5;//tonnes of refrigeration
+T1 = 273-10;//temperature of the saturated vapour in K
+T2 = 273+35;//temperature of the super heated vapour in K
+T3 = 273+25;//temperature of the saturated liquid in K
+T4 = 273+25;//temperature of the wet vapour in K
+H1 = 341.8;//enthalpy of the saturated vapour in Kcal/Kg
+H2 = 409.0;//enthalpy of the super heated vapour in Kcal/Kg
+H3 = 350.0;//enthalpy of the saturated liquid in Kcal/Kg
+H4 = 71.3;//enthalpy of the wet vapour in Kcal/Kg
+
+//To Calculate the C.O.P, mass of refrigerant required, compressor horse power required and the C.O.P & compressor horse power for a reversed Carnot cycle
+//(i)Calculation of the C.O.P of the compression cycle
+//From equation 12.6 (page no 226)
+C.O.P = (H1-H4)/(H2-H1);
+mprintf('(i)C.O.P of the compression cycle is %f',C.O.P);
+
+//(ii)Calculation of mass of refrigerant required
+//From equation 12.7 (page no 226)
+M = (m*50.4)/(H1-H4);
+mprintf('\n (ii)The mass of refrigerant required is %f Kg/mt',M);
+
+//(iii)Calculation of the compressor horse power
+//From equation 12.5 (page no 226)
+C_hp = (H2-H1)*M*(427/4500);
+mprintf('\n (iii)The compressor horse power is %f hp',C_hp);
+
+//(iv)Calculation for reversed Carnot cycle
+//From equation 12.1 (page no 220)
+C.O.P = T1/(T3-T1);
+mprintf('\n\n (iv)C.O.P for the reversed Carnot cycle is %f',C.O.P);
+Q2 = m*50.4*(427/4500);//in hp
+C_hp = Q2/C.O.P;
+mprintf('\n    Compressor horse power for the reversed Carnot cycle is %f hp',C_hp);
+//end
+\ No newline at end of file