1 files changed, 26 insertions, 0 deletions
diff --git a/409/CH29/EX29.5/Example29_5.sce b/409/CH29/EX29.5/Example29_5.sce
new file mode 100755
index 000000000..78f28eb6e
--- /dev/null
+++ b/409/CH29/EX29.5/Example29_5.sce
@@ -0,0 +1,26 @@
+clear ;
+clc;
+// Example 29.5
+printf('Example 29.5\n\n');
+//page no. 902
+// Solution fig. E29.5
+
+// Given 
+W = 100 ;// Amount of entering water -[lb/hr]
+H1 = .020 ;// Humidity of entering air -[lb H2O / lb dry air]
+T1 = 155 ;//Temperature of entering air -[degree F]
+DTB = 110 ;// Dry bulb temperature of exit air -[degree F]
+WTB = 100 ;// Wet bulb temperature of exit air -[degree F]
+
+// Additional data is obtained from humidity chart, it is as follows
+H2 = .0405 ;//Humidity of exit air -[lb H2O / lb dry air]
+
+del_H = H2 - H1 ;// Change in humidity betwween two states -[lb H2O / lb dry air]
+air_in = (W*1.02)/(del_H * 1)   ;// Amount of wet air entering -[lb]
+
+mol_air = 29 ;// Molecular wt. of air -[lb]
+Ref_T = 32 + 460 ;// Reference temperature - [ degree R]
+gi_T = 90 + 460; // Given temperature on which calculation is based - [degree R] 
+air = (air_in *359*gi_T)/( mol_air*Ref_T) ;// Air consumption of dryer at 90 degree F and 1 atm -[cubic feet]
+
+printf('Air consumption of dryer at 90 degree F and 1 atm  is %.2e cubic feet .\n',air);
+\ No newline at end of file