diff options
Diffstat (limited to '409/CH26/EX26.1/Example26_1.sce')
| -rwxr-xr-x | 409/CH26/EX26.1/Example26_1.sce | 33 |
1 files changed, 33 insertions, 0 deletions
diff --git a/409/CH26/EX26.1/Example26_1.sce b/409/CH26/EX26.1/Example26_1.sce new file mode 100755 index 000000000..b12a393d9 --- /dev/null +++ b/409/CH26/EX26.1/Example26_1.sce @@ -0,0 +1,33 @@ +clear ; +clc; +// Example 26.1 +printf('Example 26.1\n\n'); +//page no. 804 +// Solution + +printf('Table to carry out degree of freedom analysis:\n'); +// Number of variables involved +printf('\nI. Number of variables involved.\n'); +printf(' Species in F1 1 \n'); +printf(' Species in F2 2\n'); +printf(' Specie in F3 5\n'); +printf(' Total stream flows 3\n'); +printf(' Stream temperatures 3\n'); +printf(' Stream pressures 3 \n'); +printf(' Q 1 \n'); +printf(' Extent of reactions 2\n'); +printf('\__________________________________________________________________________________________\n'); +printf(' Total 20\n'); +printf('\n\nII. Number of equations and specifications.\n'); +printf(' Independent species material balances 6\n'); +printf(' Sum of species in each of the two streams 2 \n'); +printf(' Energy balance 1\n'); +printf(' Total stream flows 2\n'); +printf(' Species values(CO) 1\n'); +printf(' Pressures 3 \n'); +printf(' Temperatures 2 \n'); +printf(' O2 to N2 ratio specified in F2 1 \n'); +printf(' Complete reaction, hence the extent of reaction is implied to both reactions 2\n'); +printf('\___________________________________________________________________________________________\n'); +printf(' Total 20\n'); +printf('\n Therefore, by analysing the above table it is clear that degrees of freedom of system is (20 - 20) = 0 \n');
\ No newline at end of file |