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+//Value of P
+//Refer fig. 5.5 (a),(b)&(c)
+//(a) when P is Horizontal Phor
+//Consider equilibrium
+//block A
+N1=1000  //N
+F1=0.25*N1  //N
+T=F1  //N 
+//Block B
+N2=N1+2000  //N
+F2=3000/3  //mu*N2  N
+Phor=F1+F2  //N
+//(b) when P is inclined  (Pinc)
+//Considering equilibrium of block B
+//Using law of friction
+//Pinc*cosd(30)-F1-F2=0
+Pinc=1250/(cosd(30)+(0.5/3))  //N
+printf("\nPhor=%0.2d N\nPinc=%0.2d N",Phor,Pinc)
+