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+//Finding unknown forces
+//Refer fig. 4.8
+//Let us assume joint E as origin,EC as x-axis,EA as y-direction
+//accordingly the co-ordinates are
+//A(0,3),B(3,3),C(6,0),D(3,0),E(0,0)
+YD=-40 //kN
+YC=-40 //kN
+//Using co-ordinates lengths are found out to be
+LAB=3 //m
+LBC=3*sqrt(2) //m
+LCD=3 //m
+LDE=3 //m
+LBD=3 //m
+LBE=3*sqrt(2) //m
+//Consider joint C
+//applying equilibrium conditions
+tCB=40/3
+tCD=-40/3
+FCB=tCB*LBC //kN
+FCD=-13.333*LCD //kN
+//Consider joint D
+//applying equilibrium conditions
+tDE=tCD
+FDE=tCD*LCD //kN
+tDB=40/3
+FDB=tDB*LBD
+//Consider joint B
+//applying equilibrium conditions
+tBE=-(13.333+13.333)
+FBE=tBE*LBE //kN
+tBA=40
+FBA=tBA*LAB
+printf("The required forces are:-\nForce in member AB=%.2d kN\nForce in member BC=%.2d kN\nForce in member CD=%.2d kN\nForce in member DE=%.2d kN\nForce in member EB=%.2d kN\nForce in member BD=%.2d kN",FBA,FCB,FCD,FDE,FBE,FDB)