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-rw-r--r--3886/CH3/EX3.5/3_5.txt3
-rw-r--r--3886/CH3/EX3.5/Ex3_5.sce17
2 files changed, 20 insertions, 0 deletions
diff --git a/3886/CH3/EX3.5/3_5.txt b/3886/CH3/EX3.5/3_5.txt
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+++ b/3886/CH3/EX3.5/3_5.txt
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+
+--> exec('E:\My program EM\3. Resultant and equilibrium of system of coplanar non-concurrent forces\Ex3_5.sce', -1)
+The resultant of the system is R=4.656 kN as shown in fig. 3.14(b) \ No newline at end of file
diff --git a/3886/CH3/EX3.5/Ex3_5.sce b/3886/CH3/EX3.5/Ex3_5.sce
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+//Find the resultant
+//refer fig. 3.14 (a) and (b)
+theta1=atand(10/10)
+theta2=atand(30/40)
+theta3=atand(10/20)
+Rx=2*cosd(theta1)+5*cosd(theta2)-1.5*cosd(theta3) //kN
+Ry=2*sind(theta1)-5*sind(theta2)-1.5*sind(theta3) //kN
+R=sqrt(Rx^2+Ry^2) //kN
+alpha=atand(-Ry/Rx) //Degree
+//Moment of forces about O is
+MO=2*30*cosd(45)+5*50*sind(theta2)+1.5*10*sind(theta3) //kN-mm
+//distance d of resultant R from O is given as
+d=MO/R
+printf("The resultant of the system is R=%.3f kN as shown in fig. 3.14(b)",R)
+
+
+