2 files changed, 29 insertions, 0 deletions
diff --git a/3886/CH2/EX2.19/2_19.txt b/3886/CH2/EX2.19/2_19.txt
new file mode 100644
index 000000000..45ecb131a
--- /dev/null
+++ b/3886/CH2/EX2.19/2_19.txt
@@ -0,0 +1,8 @@
+ 
+--> exec('E:\My program EM\2. Resultant and equilibrium of system of coplanar concurrent forces\Ex2_19.sce', -1)
+
+The required values are:-
+T1=38.97 kN
+T2=23.85 kN
+T3=22.50 kN
+theta=54.77 degree
+\ No newline at end of file
diff --git a/3886/CH2/EX2.19/Ex2_19.sce b/3886/CH2/EX2.19/Ex2_19.sce
new file mode 100644
index 000000000..609b37097
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+++ b/3886/CH2/EX2.19/Ex2_19.sce
@@ -0,0 +1,21 @@
+//determine tension and inclination
+//Refer fig. 2.24 (a),(b) and (c)
+//consider equilibrium at point B,we get
+//T2*sind(theta)=T1*sind(30)...(1)
+//T2*cosd(theta)=T1*sind(30)-20...(2)
+//consider equilibrium at point C,we get
+//T2*sind(theta)=T3*sind(60)...(3)
+//T2*cosd(theta)=-T3*cosd(60)+25...(4)
+//solving (1) and (3) we get
+//T1=T3*sqrt(3)...(5)
+//solving (2) and (4) and substituting (5) we get
+T3=45/2  //kN
+T1=T3*sqrt(3)  //kN
+//then (1)/(2) gives
+theta=atand(1.416)  //degree
+T2=19.48/sind(theta)  //kN
+printf("\nThe required values are:-\nT1=%.2f kN\nT2=%.2f kN\nT3=%.2f kN\ntheta=%.2f degree",T1,T2,T3,theta)
+
+
+
+