2 files changed, 72 insertions, 0 deletions
diff --git a/3886/CH2/EX2.14/2_14.txt b/3886/CH2/EX2.14/2_14.txt
new file mode 100644
index 000000000..7a8b93f7d
--- /dev/null
+++ b/3886/CH2/EX2.14/2_14.txt
@@ -0,0 +1,47 @@
+ --> // Finding magnitude of F
+--> //When F is applied at point B,refer fig 2.18(a)and(b)
+--> //From triangle AOC
+--> OC=300-150
+ OC  = 
+
+   150.
+--> AO=300
+ AO  = 
+
+   300.
+--> alpha=acosd(OC/AO)  //degree
+ alpha  = 
+
+   60.
+--> //from triangle AOB using geometry we get angle OBA=30 degree
+--> //Resolving the forces we get
+--> R=2000/cosd(30)  //N
+ R  = 
+
+   2309.4011
+--> F=R*sind(30)  //N
+ F  = 
+
+   1154.7005
+--> printf("Least force through point B is F=%.1f N",F)
+Least force through point B is F=1154.7 N--> //Least force required through the centre of roller
+--> //Assume that F makes an angle theta with the horizontal
+--> //Refer fig. 2.19 (a) and (b)
+--> //Resolving the forces we get
+--> //F*cosd(theta)=R*sind(60)...(1)
+--> //F*sind(theta)+R*cosd(60)=W...(2)
+--> //Solving (1) and (2) we get
+--> //sind(theta)+cotd(60)*cosd(theta)=W/F
+--> //For obtaining maximum value of W/F we differentiate W/F w.r.t. theta and we get
+--> theta=acotd(cotd(60))  //degree
+ theta  = 
+
+   60.
+--> //Least value of F is observed when it is at right angle to reaction R
+--> Fmin=2000*sind(60)  //N
+ Fmin  = 
+
+   1732.0508
+--> printf("\nLeast force through the centre of roller is Fmin=%.0f N",Fmin)
+
+Least force through the centre of roller is Fmin=1732 N
+\ No newline at end of file
diff --git a/3886/CH2/EX2.14/Ex2_14.sce b/3886/CH2/EX2.14/Ex2_14.sce
new file mode 100644
index 000000000..4d9c976e3
--- /dev/null
+++ b/3886/CH2/EX2.14/Ex2_14.sce
@@ -0,0 +1,25 @@
+// Finding magnitude of F
+//When F is applied at point B,refer fig 2.18(a)and(b)
+//From triangle AOC
+OC=300-150
+AO=300
+alpha=acosd(OC/AO)  //degree
+//from triangle AOB using geometry we get angle OBA=30 degree
+//Resolving the forces we get
+R=2000/cosd(30)  //N
+F=R*sind(30)  //N
+printf("Least force through point B is F=%.1f N",F)
+//Least force required through the centre of roller
+//Assume that F makes an angle theta with the horizontal
+//Refer fig. 2.19 (a) and (b)
+//Resolving the forces we get
+//F*cosd(theta)=R*sind(60)...(1)
+//F*sind(theta)+R*cosd(60)=W...(2)
+//Solving (1) and (2) we get
+//sind(theta)+cotd(60)*cosd(theta)=W/F
+//For obtaining maximum value of W/F we differentiate W/F w.r.t. theta and we get
+theta=acotd(cotd(60))  //degree
+//Least value of F is observed when it is at right angle to reaction R
+Fmin=2000*sind(60)  //N
+printf("\nLeast force through the centre of roller is Fmin=%.0f N",Fmin)
+