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+//batsman
+//refer fig 17.2 (a) and (b)
+//Let Fx be the horizontal component and Fy be the vertical component
+//Applying impulse momentum equation in horizontal direction
+Fx=(48*cosd(30)+20)/(9.81*0.02) //N
+//Applying impulse momentum equation in vertical direction
+Fy=(48*sind(30))/(9.81*0.02) //N
+//Resultant force
+F=sqrt(((Fx)^2)+((Fy)^2)) //N
+theta=atand(Fy/Fx) //degree
+printf("\nF=%.3f N\ntheta=%.3f degree",F,theta)
+
+