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+//Small block sliding down the plane
+//refer fig. 16.11 (a),(b) and (c)
+//Length AB
+AB=sqrt((3^2)+(4^2))
+//Consider FBD of the block on inclined plane A
+//It moves down the plane, hence
+//N1=W*0.8
+mu=0.3
+//F1=0.3*W
+//Applying work energy equation for the motion from A to B
+vB=sqrt((0.6-0.24)*5*2*9.81)  //m/sec
+//For the motion on horizontal plane
+//final velocity=0
+//Writing work energy equation for the motion along BC
+s=(5.943^2)/(2*9.81*0.3)  //m
+printf("\ns=%.2f m",s)
+
+