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+//Pump
+//Work done in lifting 40 m^3 of water to a height of 50 m (W1)
+W1=40*9810*50 //N-m
+//Kinetic energy at delivery KE1
+KE1=(40*9810*25)/(2*9.81) //N-m
+//Total energy spent (TE)
+TE=19620000+500000 //N-m
+//This energy is spent by the pump in half an hour
+//Pump output power (PO)
+PO=(20120000)/(1800*1000) //kW
+//Input power (Ip)
+Ip=PO/0.7 //kW
+printf("\Energy spent=%.2f N-m\nInput power=%.4f kW",TE,Ip)
+
+