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+//block on horizontal plane
+//refer fig. 15.6 (a) and (b)
+//Inertia force of block m*a=3/9.81 kN
+//applying equilibrium conditions
+//N=1+P/2
+//P*cosd(30)-F-3/9.81
+//From law of friction
+//F=mu*N
+//Solving above equations
+P=((3/9.81)+(0.25))/(cosd(30)-(0.125)) //kN
+printf("\nP=%.3f kN",P)
+//The answers vary due to round off error