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+//Crossing of balls
+//refer fig. 12.8
+//1.for motion of first ball
+au=0
+//1s=30-h
+aa=9.81  //m/sec^2
+//2.for motion of second ball
+bu=15  //m/sec
+//s=h
+ba=-9.81  //m/sec^2
+//30-h=0*t+(9.81*t^2)/2  ...(1)
+//h=15*t-(9.81*t^2)/2  ...(2)
+//solving (1) and (2)
+t=30/15
+h=15*2-(9.81*2^2)/2  //m
+//at t=2
+//downward velocity of first ball
+v1=0+9.81*2  //m/sec
+//Upward velocity of second ball
+v2=15-9.81*2  //m/sec
+//relative velocity vr
+vr=v1-(-v2)  //m/sec
+printf("\nt=%.2f sec\nh=%.2f m\nvr=%.2f m/sec",t,h,vr)
+