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+//Book - Power System: Analysis & Design 5th Edition
+//Authors - J. Duncan Glover, Mulukutla S. Sarma, and Thomas J. Overbye
+//Chapter - 7 ; Example 7.3
+//Scilab Version - 6.0.0 ; OS - Windows
+clc;
+clear;
+Srated = 100; //rated power in MVA
+V1 = 13.8; //generator supply voltage in kV
+Xg = 0.15; //generator input reactance in ohm
+Vline = 138; //transmission line voltage in kV
+Xline = 20; //transmission line reactance in ohm
+Vprtr1 = 13.8; //primary side voltage of transformer 1 in kV
+Vsectr1 = 138; //secondary side voltage of transformer 1 in kV
+Xt1 = 0.10; //reactance of transformer 1 in ohm
+Vprtr2 = 138; //primary side voltage of transformer 2 in kV
+Vsectr2 = 13.8; //secondary side voltage of transformer 2 in kV
+Xt2 = 0.10; //reactance of transformer 2 in ohm
+V2 = 13.8; //motor supply voltage in kV
+Xm = 0.20; //motor reactance in ohm
+pf =0.95; //lagging power factor
+Rth1 = 0.15; //thevenins resistance in ohm
+Rth2 = 0.505; //thevenins resistance in ohm
+Vf=1.05; //prefaault voltage at the generator terminals
+Zbl = (Vsectr1^2); //base impedance of the transmission line in ohm
+Xlinepu = Xline/Zbl; //transmission line reactance in per unit
+Zth = %i*((Rth1*Rth2)/(Rth1+Rth2)); //Thevenin's impedance per unit
+If = Vf/Zth; //sub transient fault current in per unit
+Ig1 = ((Rth2/(Rth2+Rth1))*If); //sub tranisent generator current in per unit
+Im1 = ((Rth1/(Rth2+Rth1))*If); //sub transient motor current in per unit
+Ibase = (Srated/((sqrt(3))*(V1))); // generator base current in kA
+Il = ((Srated/((sqrt(3))*V1*Vf))*(cos(-acos(pf))+%i*sin(-acos(pf)))); //prefault generator current in kA
+Il = Il/Ibase; //prefault generator current in per unit
+Ig = Ig1 + Il; //sub transient generator current including pre fault current in per unit
+Im = Im1 - Il; //sub transient motor current including pre fault current in per unit
+
+printf('\n Sub transient fault current If = %0.3fi per unit',imag(If));
+printf('\n Sub transient generator current neglecting fault current Ig1 = %0.3fi per unit ',imag(Ig1));
+printf('\n Sub transient motor current neglecting fault current Im1 = %0.3fi per unit ',imag(Im1));
+printf('\n Sub transient generator current including fault current in per unit is %0.4f and its anglle is %0.4f', abs(Ig), atand(imag(Ig), real(Ig)));
+printf('\n Sub transient motor current including fault current in per unit %0.4f and its anglle is %0.4f',abs(Im), atand(imag(Im), real(Im))+360);
+//360 is added to get positive angle. There will not be any change in angle because 360 degree and 0 degree are same.