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+//Book - Power System: Analysis & Design 5th Edition
+//Authors - J. Duncan Glover, Mulukutla S. Sarma, and Thomas J. Overbye
+//Chapter - 6 ; Example 6.8
+//Scilab Version - 6.0.0 ; OS - Windows
+
+clc;
+clear;
+
+y=[15;50];                       //Constant coefficients in the equations
+x=[4;9];                         //Initial values for x1 and x2
+
+err=1;                           //Initialization of error value
+tol=1e-4;                        //Tolerance value for Newton Raphson method
+iter=0;                          //Initialization of iteration value
+
+while err>tol
+    temp=x;
+    f=[x(1)+x(2);x(1)*x(2)]                     //Function Value
+    dely=y-f;
+    J=[1 1;x(2) x(1)];                          //Jacobian Matrix
+    //Reduction of Jacobian using Gauss elimination
+    Jg=[J(1,1) J(1,2);0 J(2,2)-J(2,1)/J(1,1)]   
+    delyg=[dely(1);dely(2)-dely(1)*J(2,1)/J(1,1)]  
+    //Solution using back substitution
+    delx2=delyg(2)/Jg(2,2);
+    delx1=(delyg(1)-Jg(1,2)*delx2)/Jg(1,1)
+    delx=[delx1;delx2]
+    x=x+delx
+    err=max(abs((x(1)-temp(1))/temp(1)),abs((x(2)-temp(2))/temp(2)));
+    iter=iter+1;  
+    //Displaying first iteration results  
+    if iter==1
+        printf('Values of x1 and x2 at the end of first iteration are:\n')
+        printf('       x1=%.4f and x2=%.4f\n\n',x(1),x(2))
+    end
+end
+printf('The convergence criterion is satisfied at the %dth iteration\n',iter)
+printf('The solution is x1=%.4f and x2=%.4f',x(1),x(2))
+