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+clear
+//
+
+//Initilization of Variables
+
+t=40 //degree celsius //temperature
+A_s=400 //mm**2 //Area of steel bar
+A_c=600 //mm**2 //Area of copper bar
+E_s=2*10**5 //N/mm**2 //Modulus of Elasticity of steel bar
+E_c=1*10**5 //N/mm**2 //Modulus of Elasticity of copper bar
+alpha_s=12*10**-6 //degree celsius //Temperature coeff of steel bar
+alpha_c=18*10**-6 //degree celsius //Temperature coeff of copper bar
+L_c=800 //mm //Length of copper bar
+L_s=600 //mm //Length of steel bar
+
+//Calculations
+
+//Let P_s be the tensile force in steel bar and P_c be the compressive force in copper bar
+//Static Equilibrium obtained by taking moment about A
+//P_c=2*P_s
+
+//From property of similar triangles we get
+//(alpha_c*Lc-dell_c)*1**-1=(alpha_s*L_s-dell_s)*2**-1
+//After substituting values in above equations and further simplifying we get
+P_s=(2*alpha_c*L_c-alpha_s*L_s)*t*(L_s*(A_s*E_s)**-1+4*L_c*(A_c*E_c)**-1)**-1
+P_c=2*P_s
+
+//Stress in steel rod
+sigma_s=P_s*A_s**-1 //N/mm**2
+
+//Stress in copper rod
+sigma_c=P_c*A_c**-1 //N/mm**2
+
+//Result
+printf("\n Stress in steel rod is %0.2f N/mm**2",sigma_s)
+printf("\n STress in copper rod is %0.2f N/mm**2",sigma_c)