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+clear
+//
+
+//variable declaration
+
+//summation of all horizontal forces is zero & vertical forces is zero.
+P1=(60) //inclined down to right Load at angle 60 at 1m from A,KN
+P2=(80) //Inclined down to left Load at angle 75° at 3m from A,KN
+P3=(50) //Inclined down to left Load at angle 60° at 5.5m from A,KN
+theta1=60
+theta2=75
+theta3=60
+thetaRb=60
+//horizontal,vertical component at A is Ha,Va respectively.
+
+Rb=(P1*1*sin(theta1*%pi/180)+P2*3*sin(theta2*%pi/180)+P3*5.5*sin(theta3*%pi/180))/(6*sin(thetaRb*%pi/180)) //reaction at B point,KN
+Ha=-P1*cos(theta1*%pi/180)+P2*cos(theta2*%pi/180)-P3*cos(theta3*%pi/180)+Rb*cos(thetaRb*%pi/180)
+printf("\n RB= %0.4f KN",Rb)
+
+//now vertical component
+Va=P1*sin(theta1*%pi/180)+P2*sin(theta2*%pi/180)+P3*sin(theta3*%pi/180)-Rb*sin(thetaRb*%pi/180)
+
+Ra=sqrt((Ha**2)+(Va**2))
+
+printf("\n RA= %0.4f KN",Ra)
+
+alpha=(atan(Va/Ha))*180/%pi
+
+printf("\n alpha= %0.2f °",alpha)