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+clear
+//
+
+//variable declaration
+
+Db=(20) //diameter of brass rod,mm
+Dse=(40) //external diameter of steel tube,mm
+Dsi=(20) //internal diameter of steel tube,mm
+Es=(2*100000 ) //Young's modulus steel, N/mm^2
+Eb=(1*100000 ) //Young's modulus brass, N/mm^2
+alphas=(0.0000116) //coeffcient of expansion of steel,/°C
+alphab=(0.0000187) //coeffcient of expansion of brass,/°C
+t=60 //raise in temperature, °C
+As=%pi*((Dse**2)-(Dsi**2))/4 //Area of steel tube** mm^2
+Ab=%pi*((Db**2))/4 //Area of brass rod**mm^2
+L=1200 //length,mm
+//Since free expansion of brass is more than free expansion of steel , compressive force Pb develops in brass and tensile force Ps develops in steel to keep the final position at CC
+
+//Horizontal equilibrium condition gives Pb = Ps, say P.
+
+P=((alphab-alphas)*t*L)/((L/(As*Es))+(L/(Ab*Eb)))
+
+ps=P/As
+pb=P/Ab
+
+printf("\n stress in steel= %0.2f N/mm^2",ps)
+printf("\n Stress in brass= %0.2f N/mm^2",pb)
+
+//the pin resist the force P at the two cross- sections at junction of two bars.
+
+Shearstress=P/(2*Ab)
+printf("\n Shear stress in pin %0.2f N/mm^2",Shearstress)