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+clear
+// The section is divided into three rectangles A1, A2 and A3
+
+//
+
+//variable declaration
+
+
+A1=80.0*12.0 //Area of 1,mm^2
+A2=(150.0-22.0)*12.0 //Area of 2,mm^2
+A3=120.0*10.0 //Area of 3,mm^2
+
+A=A1+A2+A3 //Total area,mm^2
+
+//Due to symmetry, centroid lies on axis y-y. The bottom fibre (1)–(1) is chosen as reference axis to locate the centroid
+
+Y1=150-6
+Y2=(128/2) +10
+Y3=5
+X1=60.0
+X2=60.0
+X3=60.0
+
+yc=(A1*X1+A2*X2+A3*X3)/A
+
+
+
+xc=(A1*Y1+A2*Y2+A3*Y3)/A
+
+//With reference to the centroidal axis x-x and y-y, the centroid of the rectangles A1 is g1 (0.0, 150-6-yc), that of A2 is g2 (0.0, 75-yc) and that of A3 is g3 (0.0, yc-5 ).
+
+Iyy=(12*((80**3))/12)+(128*((12**3))/12)+(10*((120**3))/12)
+
+Ixx=(80.0*(12.0**3)/12.0)+(A1*((150-6-yc)**2))+(12*(128**3.0)/12.0)+(A2*((75-yc)**2))+(120*(10**3)/12.0)+(A3*((150-10-6-yc)**2))
+
+
+
+PolarmomentofInertia=Ixx+Iyy
+
+printf("\n Polar moment of Inertia= %0.0f mm^4",PolarmomentofInertia)
+
+kxx=sqrt(Ixx/A)
+printf("\n kxx= %0.2f mm",kxx)
+
+
+kyy=sqrt(Iyy/A)
+printf("\n kyy= %0.2f mm",kyy)