1 files changed, 42 insertions, 0 deletions
diff --git a/3862/CH3/EX3.2/Ex3_2.sce b/3862/CH3/EX3.2/Ex3_2.sce
new file mode 100644
index 000000000..91f36f6f2
--- /dev/null
+++ b/3862/CH3/EX3.2/Ex3_2.sce
@@ -0,0 +1,42 @@
+clear
+//
+
+//Now, we cannot find a joint with only two unknown forces without finding reactions.
+//Consider the equilibrium of the entire frame,Sum of moments about A is zero,Horizontal forces & Vertical forces is zero.
+
+//variable declaration
+
+PB=40.0
+PC=50.0
+PE=60.0
+
+theta=60.0
+
+RD=(PC*3+PE*2+PB*1)/(4.0)
+
+RA=PB+PC+PE-RD
+
+FAB=RA/sin(theta*%pi/180)
+
+printf("\n FAB= %0.4f KN (Comp.)",FAB)
+
+FAE=FAB*cos(theta*%pi/180)
+
+printf("\n FAE= %0.4f KN (Tension)",FAE)
+
+FDC=RD/sin(theta*%pi/180)
+
+printf("\n FDC= %0.4f KN (Comp.) ",FDC)
+
+FDE=FDC*cos(theta*%pi/180)
+
+printf("\n FDE= %0.4f KN (Tension) ",FDE)
+
+FBE=(FAB*sin(theta*%pi/180)-PB)/sin(theta*%pi/180)
+
+FBC=(FAB+FBE)*(0.5)
+printf("\n FBC= %0.4f KN (Comp.)",FBC)
+
+
+FCE=(FDC*sin(theta*%pi/180)-PC)/(sin(theta*%pi/180))
+printf("\n FCE= %0.4f KN (Tension)",FCE)