diff options
Diffstat (limited to '3862/CH3/EX3.2/Ex3_2.sce')
| -rw-r--r-- | 3862/CH3/EX3.2/Ex3_2.sce | 42 |
1 files changed, 42 insertions, 0 deletions
diff --git a/3862/CH3/EX3.2/Ex3_2.sce b/3862/CH3/EX3.2/Ex3_2.sce new file mode 100644 index 000000000..91f36f6f2 --- /dev/null +++ b/3862/CH3/EX3.2/Ex3_2.sce @@ -0,0 +1,42 @@ +clear +// + +//Now, we cannot find a joint with only two unknown forces without finding reactions. +//Consider the equilibrium of the entire frame,Sum of moments about A is zero,Horizontal forces & Vertical forces is zero. + +//variable declaration + +PB=40.0 +PC=50.0 +PE=60.0 + +theta=60.0 + +RD=(PC*3+PE*2+PB*1)/(4.0) + +RA=PB+PC+PE-RD + +FAB=RA/sin(theta*%pi/180) + +printf("\n FAB= %0.4f KN (Comp.)",FAB) + +FAE=FAB*cos(theta*%pi/180) + +printf("\n FAE= %0.4f KN (Tension)",FAE) + +FDC=RD/sin(theta*%pi/180) + +printf("\n FDC= %0.4f KN (Comp.) ",FDC) + +FDE=FDC*cos(theta*%pi/180) + +printf("\n FDE= %0.4f KN (Tension) ",FDE) + +FBE=(FAB*sin(theta*%pi/180)-PB)/sin(theta*%pi/180) + +FBC=(FAB+FBE)*(0.5) +printf("\n FBC= %0.4f KN (Comp.)",FBC) + + +FCE=(FDC*sin(theta*%pi/180)-PC)/(sin(theta*%pi/180)) +printf("\n FCE= %0.4f KN (Tension)",FCE) |