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+clear
+//
+
+//variable declaration
+
+PA=100.0 //inclined up loading at 60° at A, N
+PB1=80.0 //Vertical down loading at B,N
+PB2=80.0 //Horizontal right loading at at B,N
+PC=120.0 //inclined down loading at 30° at C,N
+
+thetaA=60.0*%pi/180.0
+thetaB=30.0*%pi/180.0
+
+
+
+//Taking horizontal direction towards left as x axis and the vertical downward direction as y axis.
+////sum of vertical Fy & sum of horizontal forces Fx is zero
+//Assume direction of Fx is right
+//Assume direction of Fy is up
+
+Fx=PB2-PA*cos(thetaA)-PC*cos(thetaB)
+Rx=-Fx
+
+Fy=PB1+PC*sin(thetaB)-PA*sin(thetaA)
+Ry=Fy
+
+
+R=sqrt((Rx**2)+(Ry**2))
+printf("\n R= %0.2f KN",R)
+
+alpha=atan(Fy/Fx)*180/%pi
+printf("\n alpha= %0.2f °",(-alpha))
+
+//Let x be the distance from A at which the resultant cuts AC. Then taking A as moment centre,
+
+x=(PB1*100*sin(thetaA)+PB2*50+PC*sin(thetaB)*100)/Ry
+printf("\n x= %0.3f mm",x)