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+//Example 3.6: Reduce expression using k-map 
+clc; //clears the window
+clear; //clears all existing variables
+//Mapping the expression//
+disp('       W''X'' W''X  WX  WX'' ')
+disp('Y''Z''   1     1    1   1 ')
+disp('YZ''          1     ')
+disp('YZ           1    1   1')
+disp('YZ''   ')
+disp(' From the map, high outputs are for 0,1,2,3,5,13,14,15 ') //given logic equation
+a=[0 0 0 0;0 0 0 1;0 0 1 0;0 0 1 1  ;0 1 0 1 ;1 1 0 1;1 1 1 0 ;1 1 1 1']
+disp(a)
+for i=1: 8
+    if a(i,1)==1 then
+       b(i,1)='W'
+   else
+       b(i,1)='W'''
+    end
+    if a(i,2)==1 then
+       b(i,2)='X'
+   else
+       b(i,2)='X'''
+    end
+     if a(i,3)==1 then
+       b(i,3)='Y'
+   else
+       b(i,3)='Y'''
+    end
+    if a(i,4)==1 then
+       b(i,4)='Z'
+   else
+       b(i,4)=' Z'''
+    end
+end
+disp(' Evaluating expression from truth table and map ')
+x1=strcat([ b(1,1),b(1,2),b(1,3),b(1,4) ])
+x2=strcat([ b(2,1),b(2,2),b(2,3),b(2,4) ])
+x3=strcat([ b(3,1),b(3,2),b(3,3),b(3,4) ])
+x4=strcat([ b(4,1),b(4,2),b(4,3),b(4,4) ])
+x5=strcat([ b(5,1),b(5,2),b(5,3),b(5,4) ])
+x6=strcat([ b(6,1),b(6,2),b(6,3),b(6,4) ])
+x7=strcat([ b(7,1),b(7,2),b(7,3),b(7,4) ])
+x8=strcat([ b(8,1),b(8,2),b(8,3),b(8,4) ])
+x=[x1"+",x2"+",x3"+",x4"+",x5"+",x6"+",x7"+",x8]
+disp(x)
+//Expression is displayed//
+disp('Three different reduced expression using boolean algebra')
+disp('F = Y''Z'' + WYZ + W''XZ''')
+