diff options
Diffstat (limited to '3860/CH3/EX3.15')
| -rw-r--r-- | 3860/CH3/EX3.15/EX3_15.sce | 52 | ||||
| -rw-r--r-- | 3860/CH3/EX3.15/Ex3_15.txt | 33 |
2 files changed, 85 insertions, 0 deletions
diff --git a/3860/CH3/EX3.15/EX3_15.sce b/3860/CH3/EX3.15/EX3_15.sce new file mode 100644 index 000000000..e9ca3c720 --- /dev/null +++ b/3860/CH3/EX3.15/EX3_15.sce @@ -0,0 +1,52 @@ +//Example 3.15: Reduce expression using k-map
+clc; //clears the window
+clear; //clears all existing variables
+//Mapping the expression//
+disp(' A''B'' A''B AB AB'' ')
+disp('C''D'' 1 1 ')
+disp('CD'' 1 1 1 1')
+disp('CD 1 1 1')
+disp('CD'' 1 1 1')
+disp(' From the map, high outputs are for 0,2,4,5,6,7,8,10,11, 12,14,15') //given logic equation
+a=[0 0 0 0;0 0 1 0;0 1 0 0;0 1 0 1;0 1 1 0;0 1 1 1;1 0 0 0;1 0 1 0 ;1 0 1 1;1 1 0 0;1 1 1 0;1 1 1 1]
+disp(a)
+for i=1: 11
+ if a(i,1)==1 then
+ b(i,1)='A'
+ else
+ b(i,1)='A'''
+ end
+ if a(i,2)==1 then
+ b(i,2)='B'
+ else
+ b(i,2)='B'''
+ end
+ if a(i,3)==1 then
+ b(i,3)='C'
+ else
+ b(i,3)='C'''
+ end
+ if a(i,4)==1 then
+ b(i,4)='D'
+ else
+ b(i,4)=' D'''
+ end
+end
+disp(' Evaluating expression from truth table and map ')
+x1=strcat([ b(1,1),b(1,2),b(1,3),b(1,4) ])
+x2=strcat([ b(2,1),b(2,2),b(2,3),b(2,4) ])
+x3=strcat([ b(3,1),b(3,2),b(3,3),b(3,4) ])
+x4=strcat([ b(4,1),b(4,2),b(4,3),b(4,4) ])
+x5=strcat([ b(5,1),b(5,2),b(5,3),b(5,4) ])
+x6=strcat([ b(6,1),b(6,2),b(6,3),b(6,4) ])
+x7=strcat([ b(7,1),b(7,2),b(7,3),b(7,4) ])
+x8=strcat([ b(8,1),b(8,2),b(8,3),b(8,4) ])
+x9=strcat([ b(9,1),b(9,2),b(9,3),b(9,4) ])
+x10=strcat([ b(10,1),b(10,2),b(10,3),b(10,4) ])
+x11=strcat([ b(11,1),b(11,2),b(11,3),b(11,4) ])
+x=[x1"+",x2"+",x3"+",x4"+",x5"+",x6"+",x7"+",x8"+",x9"+",x10"+",x11]
+disp(x)
+//Expression is displayed//
+disp('The resulting solution is')
+disp('F = A''B'' + C''D + B''D'' + ABC')
+
diff --git a/3860/CH3/EX3.15/Ex3_15.txt b/3860/CH3/EX3.15/Ex3_15.txt new file mode 100644 index 000000000..7470e15c4 --- /dev/null +++ b/3860/CH3/EX3.15/Ex3_15.txt @@ -0,0 +1,33 @@ +
+ A'B' A'B AB AB'
+
+ C'D' 1 1
+
+ CD' 1 1 1 1
+
+ CD 1 1 1
+
+ CD' 1 1 1
+
+ From the map, high outputs are for 0,2,4,5,6,7,8,10,11, 12,14,15
+
+ 0. 0. 0. 0.
+ 0. 0. 1. 0.
+ 0. 1. 0. 0.
+ 0. 1. 0. 1.
+ 0. 1. 1. 0.
+ 0. 1. 1. 1.
+ 1. 0. 0. 0.
+ 1. 0. 1. 0.
+ 1. 0. 1. 1.
+ 1. 1. 0. 0.
+ 1. 1. 1. 0.
+ 1. 1. 1. 1.
+
+ Evaluating expression from truth table and map
+
+!A'B'C' D' + A'B'C D' + A'BC' D' + A'BC'D + A'BC D' + A'BCD + AB'C' D' + AB'C D' + AB'CD + ABC' D' + ABC D' !
+
+ The resulting solution is
+
+ F = A'B' + C'D + B'D' + ABC
\ No newline at end of file |