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+//Example 9.1
+m1=26.0;//Mass of 1st child (kg)
+m2=32.0;//Mass of 2nd child (kg)
+r1=1.60;//Distance of 1st child from pivot (m)
+r_p=0;//Distance of supporting force of pivot from pivot (m)
+g=9.80;//Acceleration due to gravity (m/s^2)
+theta=90;//Angle (deg)
+//Torque tau=r*(m*g)*sind(theta)
+//Torque due to supporting force of pivot is zero as r_p=0
+//For equilibrium,sum of torques must equal zero
+r2=(r1*m1*g*sind(theta))/(m2*g*sind(theta));//Distance of 2nd child from pivot (m)
+printf('a.Distance of 2nd child from pivot = %0.2f m',r2)
+F_p=(m1*g)+(m2*g);//Supporting force of pivot (N)
+printf('\nb.Supporting force of pivot = %0.1f N',F_p)
+//Answer varies due to round off error
+//Openstax - College Physics
+//Download for free at http://cnx.org/content/col11406/latest