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+// Example 9_10
+clc;funcprot(0);
+// Given data
+P_1=100;// kPa
+T_1=25+273;// K
+T_2a=472.0;// K
+r_p=5;// The pressure ratio
+T_3=850+273;// The maximum temperature in K
+T_4a=709.1;// K
+k=1.4;// The specific heat ratio
+c_p=1.00;// kJ/kg.K
+n_comp=0.80;// The isentropic efficiency of the compressor
+n_turb=0.80;// The isentropic efficiency of the turbine
+
+// Calculation
+w_comp=(c_p/n_comp)*(T_2a-T_1);// kJ/kg
+w_turb=n_turb*c_p*(T_3-T_4a);// kJ/kg
+w_r=w_comp/w_turb;// The back work ratio
+T_2=(w_comp/c_p)+T_1;// K
+w_net=w_turb-w_comp;// kJ/kg
+q_in=c_p*(T_3-T_2);// kJ/kg
+n=w_net/q_in;// The thermal efficiency of the cycle
+printf("\nThe back work ratio=%0.3f or %2.1f percentage. \nThe thermal efficiency of the cycle,n=%0.3f or %2.1f percentage.",w_r,w_r*100,n,n*100);