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+// Example 6_8
+clc;funcprot(0);
+// Given data
+m=2;// The mass of steam in kg
+T=400;// °C
+P=600;// kPa
+T_0=25+273;// K
+
+// Calculation
+// From steam tables
+s_1=7.7086;// kJ/kg.K
+s_2=1.9316;// kJ/kg.K
+dS_sys=m*(s_2-s_1);// kJ/K
+h_1=3270.2;// kJ/kg
+h_2=670.6;// kJ/kg
+Q=m*(h_1-h_2);// The heat transfer in kJ
+dS_surr=Q/T_0;// kJ/K
+dS_univ=dS_surr+dS_sys;// kJ/K
+printf("\nThe net entropy change of the process,dS_univ=%1.2f kJ/K",dS_univ);