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+// Example 6_5
+clc;funcprot(0);
+// Given data
+P_1=100;// The initial pressure in psia
+T_1=600;// The initial temperature in °F
+P_2=10;// The final pressure in psia
+
+// Calculation
+// From steam tables
+v_2=6.216;// ft^3/lbm
+v_1=v_2;// ft^3/lbm
+v_f2=0.0166;// ft^3/lbm
+v_g2=38.42;// ft^3/lbm
+x=(v_2-v_f2)/(v_g2-v_f2);// The quality of steam
+// From steam tables
+s_f2=0.2836;// Btu/lbm-°R
+s_fg2=1.5041;// Btu/lbm-°R
+s_1=1.7582;// Btu/lbm-°R
+s_2=s_f2+(x*s_fg2);// Btu/lbm-°R
+dels=s_2-s_1;//  Btu/lbm-°R
+u_f2=161.2;// Btu/lbm
+u_fg2=911.01;// Btu/lbm
+u_1=1214.2;// Btu/lbm
+q=[u_f2+(x*u_fg2)]-u_1;// Btu/lbm
+printf("\nThe entropy change,dels=%1.3f Btu/lbm-°R \nThe heat transfer,q=%3.0f Btu/lbm",dels,q);
+