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+// Example 3_7
+clc;funcprot(0);
+// Given data
+d=50*10^-3;// The distance in m
+K=2500;// N/m
+m=50;// kg
+d_p=10/100;// m
+P_atm=100;// The atmospheric pressure in kPa
+g=9.81;// m/s^2
+
+// Calculation
+W=m*g;// The weight in N
+A=(%pi*d_p^2)/4;// m^2
+P_1=((P_atm*10^3*A)+W)/A;// The pressure in the cylinder in Pa
+W_1=(P_1*A)*d;// J
+x_1=0;// m
+x_2=d;// m
+W_2=(1/2)*K*((x_2^2)-(x_1^2));// The work required to compress in J
+W_total=W_1+W_2;// The total work in J
+printf("\nThe total work,W_total=%2.2f J",W_total);