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+// Example 2_6
+clc;funcprot(0);
+// Given data
+// T(z)=15-0.00651°C
+z_0=0;// m
+P=101;// m
+z_1=3000;// m
+
+// Calculation
+// Using the given equation for T(z) we have
+// dP=P/(29.3)*(288-0.00651 z)
+// By solving this equation,we get
+P=101*exp(-0.368);// kPa
+printf("\nThe pressure at an elevation of 3000 m,P=%2.1f kPa.",P);