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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3843/CH2/EX2.6 | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3843/CH2/EX2.6')
-rw-r--r-- | 3843/CH2/EX2.6/Ex2_6.sce | 14 |
1 files changed, 14 insertions, 0 deletions
diff --git a/3843/CH2/EX2.6/Ex2_6.sce b/3843/CH2/EX2.6/Ex2_6.sce new file mode 100644 index 000000000..9ae0c98bb --- /dev/null +++ b/3843/CH2/EX2.6/Ex2_6.sce @@ -0,0 +1,14 @@ +// Example 2_6
+clc;funcprot(0);
+// Given data
+// T(z)=15-0.00651°C
+z_0=0;// m
+P=101;// m
+z_1=3000;// m
+
+// Calculation
+// Using the given equation for T(z) we have
+// dP=P/(29.3)*(288-0.00651 z)
+// By solving this equation,we get
+P=101*exp(-0.368);// kPa
+printf("\nThe pressure at an elevation of 3000 m,P=%2.1f kPa.",P);
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