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+clear
+//
+//given and derived
+ish=1
+il=26
+ia=25
+ra=0.4
+//phy1*i1=phy2*i2 and ish2*i2=ish1*i1
+//subtituting values in the above equation we get i2=25/ish2
+eb1=200-ia*ra
+//eb2=200-0.4*i2
+//eb1/eb2=(n1*ish1)/(n2*ish2)
+//190/(200-0.4*25/ish2)=500/(700*ish2)
+//on finding the square root we get the value of ish2 as 0.698A
+ish2=0.698
+totres=200/0.698
+r=totres-200
+printf("\n resistance to be inserted in the field circuit is= %0.1f ohm",r)