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+clear
+//
+//given
+//z1=15+j20
+//z2=8-j10
+I=20
+z1=25 //in polar form at angle 53.13
+z2=12.81 //at angle -51.34
+//v=I1z1=I2z2
+//I2=1.95I1
+//from diagram I**2=(I1cosang1+I2cosang2)**2+(I2sinang2-I1sinang1)**2
+//on substituting values in the above eqn and simplifying
+I1=6.78
+printf("\n I1=6.78A")
+I2=13.22
+//substitute this in I2=1.95I1
+printf("\n I2=13.22A")
+pow1=I1**2*15
+pow2=I2**2*8
+printf("\n power loss in z1= %0.1f W",pow1)
+printf("\n power loss in z2= %0.1f W",pow2)