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+clear
+//
+//given
+n=2000 //number of turns
+flux=0.05*10**-3 //Wb
+i=10 //A
+lx=(n*flux)/i //self inductance in X
+printf("\n lx= %0.5f H",lx)
+//since coils are identical self inductance in Y=self inductance in x
+fluxlinkingX=0.75*0.05*10**-3 //Wb flux linking due to current in coil X
+fluxlinkingY=2000*0.05*0.75*10**-3 //Wb flux linkages in coil Y
+m=fluxlinkingY/5 //mutual inductance
+printf("\n m= %0.5f H",m)
+//The rate of change in current di/dt=2000A/sec --> di/dt=(10-(-10))/0.01
+rate=2000
+ey=m*rate
+printf("\n The induced emf in coil Y= %0.0f V",ey)