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+// Example 5_3
+clc;funcprot(0);
+// Given data
+Q_B=950*10^5;// kJ/h
+W_p=23.0;// kW
+Q_c=-600*10^5;// kJ/h
+
+// Calculation
+Q_net=(Q_B+Q_c);// kJ/h
+W_T_net=Q_net/3600;// kJ/h
+W_T_net=W_T_net/1000;// MW
+W_T_total=(W_T_net*10^3)+W_p;// kW
+printf("\nThe net power of the turbine,(W_T)_total=%4.0f kW(round off error)",W_T_total);
+// The answer vary due to round off error