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+// Example 12_6
+clc;funcprot(0);
+// Given data
+T=25.0;// °C
+p_m=.101*10^3;// MPa
+phi=56.8/100;// The relative humidity
+
+// Calculation
+// (a)
+// From Table C.1b, we find that
+p_sat=0.003169;// MPa
+p_w=phi*p_sat*10^3;// kPa
+// (b)
+// From Dalton’s law for partial pressure, we can find the partial pressure of the dry air in the mixture as
+p_a=p_m-p_w;// kPa
+w=0.622*(p_w/p_a);// kg H2O per kg of dry air
+// (c)
+// Using Eq. (12.27) and Table C.2b, we find the dew point temperature to be
+T_sat=15.8;// °C
+T_DP=T_sat;// °C
+printf("\n(a)The partial pressure of the water vapor in the atmosphere,p_w=%1.2f kPa \n(b)The humidity ratio of the atmosphere,w=%0.4f kg H2O per kg of dry air \n(c)The dew point temperature of the atmosphere,T_DP=%2.1f°C",p_w,w,T_DP);