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+// Example 12_1
+clc;funcprot(0);
+// Given data
+w_propane=0.500;// The mass fraction
+w_air=0.500;// The mass fraction
+R=8.3143;// kJ/kgmole.K
+
+// Calculation
+// (a)
+// The molecular masses of the components are found in Table C.13 in Thermodynamic Tables to accompany Modern Engineering Thermodynamics as
+M_propane=44.09;// kg/kgmole
+M_air=28.97;// kg/kgmole
+M_m=1/((w_propane/M_propane)+(w_air/M_air));// kg/kgmole
+// (b)
+X_propane=w_propane*(M_m/M_propane);// The molar value for propane
+X_air=w_air*(M_m/M_air);// The molar value for air
+w_m=w_propane+w_air;// The mass of the mixture
+X_m=X_propane+X_air;// The molar value of the mixture
+// (c)
+R_m=R/M_m;// The equivalent gas constant in kJ/kg.K
+printf("\n(a)The equivalent molecular mass of the mixture,M_m=%2.1f kg/kgmole \n(b)The mixture composition on a molar basis,X_propane=%0.3f & X_air=%0.3f \n(c)The equivalent gas constant of the mixture,R_m=%0.3f kJ/kg.K",M_m,X_propane,X_air,R_m);