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+// Exa 17.19
+
+clc;
+clear;
+
+// Given
+
+// A Capacitive Transducer
+d = 2.5; // plate separation in mm
+A = 600; // Area (in mm^2)
+P = 8*10^5; // Pressure applied in N/m^2
+x = 0.5; // deflection produced in mm
+C = 400*10^-12; // Capacitence in farad
+
+// Solution
+
+// Since, C = e*A/d
+ e =C*d/A;
+
+printf('Since we have to find capacitence when no pressure is applied. At that time plate separation = %d mm \n', d-x);
+
+d1 = d-x; // plate separation(mm) after pressure applied 
+C1 = e*A/d1;
+
+printf(' The value of capacitence, C with d = 2mm  = %d micro farad \n', C1*10^12);