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+// Exa 5.7
+
+clc;
+clear;
+
+// Given
+
+b2 =2.5 ; // Max no of divisions on y-axis
+b1 = 1.25; // point of intersection on y-axis(div)
+
+// Solution
+
+printf(' Let theta be the phase angle of V2 w.r.t V1 where V1 and V2 are the voltages applied to x and y axis respectively \n');
+// Sin theta = b1/b2;
+Theta = asind(b1/b2);
+
+printf(' Therefore, the phase angle of V2 w.r.t V1 = %d degrees \n. But another possible value is(360-theta) i.e. %d degrees \n',Theta,360-Theta);