diff options
Diffstat (limited to '3830/CH4')
| -rw-r--r-- | 3830/CH4/EX4.1/Ex4_1.sce | 19 | ||||
| -rw-r--r-- | 3830/CH4/EX4.2/Ex4_2.sce | 40 | ||||
| -rw-r--r-- | 3830/CH4/EX4.3/Ex4_3.sce | 17 | ||||
| -rw-r--r-- | 3830/CH4/EX4.4/Ex4_4.sce | 15 | ||||
| -rw-r--r-- | 3830/CH4/EX4.5/Ex4_5.sce | 18 | ||||
| -rw-r--r-- | 3830/CH4/EX4.6/Ex4_6.sce | 29 | ||||
| -rw-r--r-- | 3830/CH4/EX4.7/Ex4_7.sce | 20 | ||||
| -rw-r--r-- | 3830/CH4/EX4.8/Ex4_8.sce | 15 | ||||
| -rw-r--r-- | 3830/CH4/EX4.9/Ex4_9.sce | 19 |
9 files changed, 192 insertions, 0 deletions
diff --git a/3830/CH4/EX4.1/Ex4_1.sce b/3830/CH4/EX4.1/Ex4_1.sce new file mode 100644 index 000000000..25e272882 --- /dev/null +++ b/3830/CH4/EX4.1/Ex4_1.sce @@ -0,0 +1,19 @@ +// Exa 4.1
+
+clc;
+clear;
+
+// Given
+
+// An oscilloscope
+
+R = 400; // Resistance(k Ohms)
+C = 0.025; // capacitance(micro Farad)
+T = 0.4; // Time period of saw-tooth output waveform(msec)
+
+// Solution
+
+printf(' The percentage of non linearity i.e deviation in output can be given as t/(4*R*C)\n ');
+PD = (T*10^-3)/(4*R*10^3*C*10^-6) ;
+
+printf(' Therefore, by calculation, percent deviation = %d percent \n ',PD*100);
diff --git a/3830/CH4/EX4.2/Ex4_2.sce b/3830/CH4/EX4.2/Ex4_2.sce new file mode 100644 index 000000000..69016bfc6 --- /dev/null +++ b/3830/CH4/EX4.2/Ex4_2.sce @@ -0,0 +1,40 @@ +// Exa 4.2
+
+clc;
+clear;
+
+// Given
+
+f = 83.3 ; // frequency of sinusoidal voltage in KHz
+
+// Solution
+// part a
+
+printf('Being sunchronised, the frequency of the saw-tooth wave will be a submultiple of the signal. \n');
+
+printf(' Frequency of saw-tooth curve = %.2f kHz \n',f/10);
+F = f/10;
+printf(' Period of the saw-tooth curve = %.1f microsec \n',(1/F)*10^3);
+
+// since, Sine wave y = A sin theta
+// but y/A = 0.5(since, end of trace was at position half the amplitide away from x-axis)
+theta = asind(1/2) ;
+printf(' The 10th wave is in short of a complete since wave by %d degrees \n',theta);
+printf(' Therefore, No of full waves of sine form seen on the screen are 9 11/12 waveforms \n');
+
+// Rise time +decay time = period of wave = 120 microsec
+T = 120 ; // period in microsec
+ Rise_by_decay = (119/12) / (10- 119/12);
+DecayTime = Rise_by_decay/T;
+printf(' Decay time = %.1f microsec \n',round(DecayTime));
+printf(' Rise time = %.1f microsec \n',T-DecayTime);
+
+// part b
+
+printf(' Since, increase time base frequency = 10/4 times the final value \n');
+
+L = (10/4)* theta ;
+printf(' Length of trace blanked in degrees due to flyback time = %d degrees \n ',L);
+T_new = T*4/10;
+printf('Period of new time base = %d microsec \n',T_new);
+printf(' Rise time as per new time base = %d microsec \n',T_new-1);
diff --git a/3830/CH4/EX4.3/Ex4_3.sce b/3830/CH4/EX4.3/Ex4_3.sce new file mode 100644 index 000000000..6604a28fb --- /dev/null +++ b/3830/CH4/EX4.3/Ex4_3.sce @@ -0,0 +1,17 @@ +// Exa 4.3
+
+clc;
+clear;
+
+// Given
+
+Va = 2500; // Applied voltage(Volts)
+e = 1.602*10^-19; // Charge of electron(C)
+m = 9.107*10^-31; // Mass of electron(Kg)
+
+// Solution
+
+// For Electron beam in the oscilloscope, its velocity is given as-
+V = sqrt(2*e*Va/m);
+
+printf(' The velocity of electron beam of an oscilloscope = %.3f * 10^6 m/sec \n',V/10^6);
diff --git a/3830/CH4/EX4.4/Ex4_4.sce b/3830/CH4/EX4.4/Ex4_4.sce new file mode 100644 index 000000000..6ddf351ea --- /dev/null +++ b/3830/CH4/EX4.4/Ex4_4.sce @@ -0,0 +1,15 @@ +// Exa 4.4
+
+clc;
+clear;
+
+// Given
+
+Def_sensitivity = 0.05; // Deflection sensitivity in mm/V
+Spot_deflection = 5; // in mm
+
+// Solution
+
+AppliedVoltage = Spot_deflection/Def_sensitivity ;
+
+printf(' The applied voltage = %d V \n',AppliedVoltage);
diff --git a/3830/CH4/EX4.5/Ex4_5.sce b/3830/CH4/EX4.5/Ex4_5.sce new file mode 100644 index 000000000..063cc090f --- /dev/null +++ b/3830/CH4/EX4.5/Ex4_5.sce @@ -0,0 +1,18 @@ +// Exa 4.5
+
+clc;
+clear;
+
+// Given
+
+// A CRT under consideration
+l = 20; // length of x-deflection plates in mm
+d = 5; // distance between x-deflection plates in mm
+s = 250; // distance between screen and center of plate in mm
+Va = 3000; // applied accelerating voltage in volts
+
+// Solution
+
+Def_sensitivity = l*s/(2*d*Va) ;
+printf(' The deflection sensitivity = %.5f mm/V \n',Def_sensitivity);
+printf(' The deflection factor = %.1f V/mm \n',1/Def_sensitivity);
diff --git a/3830/CH4/EX4.6/Ex4_6.sce b/3830/CH4/EX4.6/Ex4_6.sce new file mode 100644 index 000000000..42401bbcf --- /dev/null +++ b/3830/CH4/EX4.6/Ex4_6.sce @@ -0,0 +1,29 @@ +// Exa 4.6
+
+clc;
+clear;
+
+// Given
+
+l = 25; // length of x-deflection plates in mm
+d = 1; // distance between x-deflection plates in mm
+s = 200; // distance between screen and centre of plate in mm
+Va = 3000; // applied accelerating voltage in volts
+Lt = 100; // length of trace in mm
+
+// Solution
+
+// Deflection produced = y/Vd = s*l/(2*d*Va)
+
+y = 1/2 *(Lt);
+// Therefore,
+Vd = 2*d*Va*y/(l*s) ;
+
+Vrms = Vd/sqrt(2) ;
+
+printf(' The Vrms of the applied sinusoidal voltage = %.1f V \n',Vd);
+
+Def_sensitivity = l*s/(2*d*Va) ;
+printf(' The deflection sensitivity = %.5f mm/V \n',Def_sensitivity);
+
+// The answer provided in the textbook is wrong
diff --git a/3830/CH4/EX4.7/Ex4_7.sce b/3830/CH4/EX4.7/Ex4_7.sce new file mode 100644 index 000000000..8359d25d7 --- /dev/null +++ b/3830/CH4/EX4.7/Ex4_7.sce @@ -0,0 +1,20 @@ +// Exa 4.7
+
+clc;
+clear;
+
+// Given
+
+// Two sinusoidal voltage signals are applied to vertical and horizontal plates of CRO
+
+// Solution
+printf('Theta = asin(dvo/DV');
+// Referring fig(a)
+Theta_a = asind(0) ; // dvo = 0
+printf(' Theta for trace shown in fig(a) = %d degrees\n',Theta_a);
+// Referring fig(b)
+Theta_b = asind(3/6) ; // dvo = 3 and DV =6
+printf(' Theta for trace shown in fig(b) = %d degrees\n',Theta_b);
+// Referring fig(c)
+Theta_c = asind(1/1) ; // dvo = DV = 1
+printf(' Theta for trace shown in fig(c) = %d degrees\n',Theta_c);
diff --git a/3830/CH4/EX4.8/Ex4_8.sce b/3830/CH4/EX4.8/Ex4_8.sce new file mode 100644 index 000000000..df37267b9 --- /dev/null +++ b/3830/CH4/EX4.8/Ex4_8.sce @@ -0,0 +1,15 @@ +// Exa 4.8
+
+clc;
+clear;
+
+// Given
+
+// Referring closed Lissajous pattern as shown in fig.
+wx = 2; // no of positive x-peak
+wy = 3; // no of positive y-peak
+
+// Solution
+
+fy_fx = wy/wx ;
+printf(' Ratio of frequencies between vertical and horizontal signals = %.1f \n',fy_fx);
diff --git a/3830/CH4/EX4.9/Ex4_9.sce b/3830/CH4/EX4.9/Ex4_9.sce new file mode 100644 index 000000000..068182b3e --- /dev/null +++ b/3830/CH4/EX4.9/Ex4_9.sce @@ -0,0 +1,19 @@ +// Exa 4.9
+
+clc;
+clear;
+
+// Given
+
+// Referring Lissajous pattern shown in figure
+wx = 1 ; // Sum of x-peak pattern
+wy = 2.5; // sum of y-peak pattern
+fx = 3; // frequency of horizontal signal
+
+X = wy/wx ; // X is ratio of fy/fx
+
+// Therefore, fy = 2.5*fx
+
+printf(' Frequency of vertical signal = %.1f kHz \n ',X*fx);
+
+// The answer provided in the textbook is wrong
|