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+// Exa 4.2
+
+clc;
+clear;
+
+// Given
+
+f = 83.3 ; // frequency of  sinusoidal voltage in KHz
+
+// Solution
+// part a
+
+printf('Being sunchronised, the frequency of the saw-tooth wave will be a submultiple of the signal. \n');
+
+printf(' Frequency of saw-tooth curve = %.2f kHz \n',f/10);
+F = f/10;
+printf(' Period of the saw-tooth curve = %.1f microsec \n',(1/F)*10^3);
+
+// since, Sine wave y = A sin theta
+// but y/A = 0.5(since, end of trace was at position half the amplitide away from x-axis)
+theta = asind(1/2) ;
+printf(' The 10th wave is in short of a complete since wave by %d degrees \n',theta);
+printf(' Therefore, No of full waves of sine form seen on the screen are 9 11/12 waveforms \n');
+
+// Rise time +decay time = period of wave = 120 microsec
+T = 120 ; // period in microsec
+ Rise_by_decay = (119/12) / (10- 119/12);
+DecayTime = Rise_by_decay/T;
+printf(' Decay time = %.1f microsec \n',round(DecayTime));
+printf(' Rise time = %.1f microsec \n',T-DecayTime);
+
+// part b
+
+printf(' Since, increase time base frequency = 10/4 times the final value \n');
+
+L = (10/4)* theta ;
+printf(' Length of trace blanked in degrees due to flyback time = %d degrees \n ',L);
+T_new = T*4/10;
+printf('Period of new time base = %d microsec \n',T_new);
+printf(' Rise time as per new time base = %d microsec \n',T_new-1);