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+// Formulae's from Example 1.6 are used here
+
+// Exa 1.14
+
+clc;
+clear;
+
+// Given
+
+// Referring Fig. 1.50
+Im = 100*10^-6; // Meter resistance in Amp
+Rm = 1000; // Meter resistance in Ohms
+I1 = 1; // in Amp
+I2 = 0.1; // in Amp
+I3 = 0.01; // in Amp
+
+// Solution
+
+n = I3/Im;
+Rsh = Rm/(n-1);
+printf('  Ra + Rb + Rc = Rsh; \n ');
+printf(' The value of Rsh by calculations = %.4f Ohms \n',Rsh);
+
+Rc = Im*(Rsh+Rm)/I1;
+Rb = (Im/I2)*(Rsh+Rm) - Rc;
+Ra = Rsh-(Rb+Rc);
+printf('  Ra = %.3f Ohms, Rb = %.3f Ohms and Rc = %.3f Ohms \n',Ra,Rb,Rc);
+
+//The answer provided in the textbook is wrong for Ra calculation