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+///Chapter 9 Law Of Thermodynamics
+///Example 9.1 Page No:165
+/// Find Work interaction during the 4th processes 
+///Input data
+clc;
+clear;
+Qab=720;   //Heat transfer of 1st processes in KJ 
+Qbc=-80;   //Heat transfer of 2nd processes in KJ
+Qcd=40;    //Heat transfer of 3rd processes in KJ
+Qda=-640;  //Heat transfer of 4th processes in KJ
+Wab=-90;   //Work transfer of 1st processes in KJ
+Wbc=-50;   //Work transfer of 2nd processes in KJ
+Wcd=130;   //Work transfer of 3rd processes in KJ
+
+
+///Calculation
+///From the 1st law of thermodynamic for close system undergoing a cycle.
+
+//Work interaction during the 4th processes 
+Wda=((Qab+Qbc+Qcd+Qda)-(Wab+Wbc+Wcd)); 
+
+///Output
+printf('Work interaction during the 4th processes= %f KJ \n",Wda);