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+///Chapter No 7 Fluid Mechanics
+///Example 7.16 Page No:127
+///Find continuity discharge equation
+///input data
+clc;
+clear;
+///refer figure 11
+ZA=2; //water flows section A-A in m
+DA=0.3; //datum pipe diameter at section A-A in m
+PA=550*10^3; //pressure in kPa
+VA=6; //flow velocity in m/s
+ZB=18; //water flows at section B-B in m
+DB=0.15; //datum pipe diameter at section B-B in m
+pi1=3.14; //constant
+rho=1000; //constant
+g1=9.81; //constant
+Aa=(pi1/4)*(DA)^2;
+Ab=(pi1/4)*(DB)^2;
+pi1=3.14;
+
+///calculation
+VB=((Aa*VA)/Ab); //continuity discharge equation in m/s
+//bernoulli's equation Kpa
+//(PA/rho*g)+(VA**2/2*g)+ZA=(PB/rho*g)+(VB**2/2*g)+ZB
+PB=(((PA/(rho*g1))+(VA**2/(2*g1))+ZA)-((VB**2/(2*g1))+ZB))*(rho*g1);
+
+
+///output
+printf('continuity discharge equation= %f m/s \n',VB);
+printf('bernoullis equation= %f pa \n ',PB);