1 files changed, 58 insertions, 0 deletions
diff --git a/3819/CH3/EX3.35/Ex3_35.sce b/3819/CH3/EX3.35/Ex3_35.sce
new file mode 100644
index 000000000..5caa061bc
--- /dev/null
+++ b/3819/CH3/EX3.35/Ex3_35.sce
@@ -0,0 +1,58 @@
+// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal
+// Chapter 2 - Pressure and its measurements
+// Problem 3.35
+
+//Given Data Set in the Problem
+dens=1000
+g=9.81
+L=6
+b=2.5
+d=2
+h=1.5
+FD=1
+
+//Calculations
+                    //1) horizontal accn imparted
+ //a)
+   tan_theta=(d-h)/(L/2)
+   a=g*tan_theta
+ //b)
+    h1=d/2
+    A1=d*b
+    F1=dens*g*A1*h1
+    A2=FD*b
+    h2=FD/2
+    F2=dens*g*A2*h2
+    //c)
+    F=F1-F2
+    //this too can be used ,,calulate colume V=L*b*h
+    //then.....F_=dens*V*a     //Force required to accelerate the mass of water in the tank
+    mprintf("Part 1)Force required to accelerate the mass of water in the tank is %f N \n",F)
+                        //2) horizontal accn when front bottom corner is just exposed
+    //a)
+    CE=2
+    ED=6
+    tan_theta=CE/ED
+    a=g*tan_theta           //acceleration 
+    //b)
+    h1=CE/2
+    A1=CE*b
+    F1=dens*g*A1*h1
+    F2=0
+    //c)
+    F=F1-F2
+    mprintf("Part 2) Force required to accelerate the mass of water in the tank is %f N \n",F)
+                    //2) horizontal accn when front bottom in half exposed
+    //a)
+    CE=2
+    ED=3
+    tan_theta=CE/ED
+    a=g*tan_theta           //acceleration 
+    //b)
+    h1=CE/2
+    A1=CE*b
+    F1=dens*g*A1*h1
+    F2=0
+    //c)
+    F=F1-F2
+     mprintf("Part 2) Force required to accelerate the mass of water in the tank is %f N \n",F)