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+//Book name: Fundamentals of electrical drives by Mohamad A. El- Sharkawi
+//chapter 5
+//example 5.2
+//edition 1
+//publisher and place:Nelson Engineering
+clc;
+clear;
+l=50;                             //load in hp
+f=60;                            //frequency in hertz
+n=1764;                         //full load speed in rpm
+ns=1800;                       //synchronous speed of motor in rpm
+Pr=.950;                      //rotational loss in kilowatts
+Pcu=1.600;                   //stator copper loss in kilowatt
+Pi=1.200;                   //iron loss in kilowatt
+Pout=l/1.34;               //output power at full load is 50 hp in kilowatt
+Pd=Pout+Pr;               //power developed in kilowatt
+s=(ns-n)/ns;             //slip of the motor
+Pg=Pd/(1-s);
+Pin=Pg+Pcu+Pi;         //input power in kilowatt
+efficiency=Pout/Pin;  //motor efficiency
+efficiency=efficiency*100;//efficiency in percentage
+mprintf("The efficiency of the motor is %d percentage",efficiency)