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+//Chapter 18, Example 18.8
+clc
+//Initialisation
+vcc=15 //voltage
+RC=5.6*10**3 //resistance in ohm
+RE=1.3*10**3 //resistance in ohm
+R2=13*10**3 //resistance in ohm,
+R1=82*10**3 //resistance in ohm
+pi=3.14 //pi
+fc=10 //frequency in hertz
+VBE=0.7 //base to emitter voltage
+hfe1=100
+hfe2=400
+
+//Calculation
+VB=vcc*(R2/(R1+R2)) //Quiescent base voltage
+VE=VB-VBE //Quiescent emitter voltage
+IE=VE/RE //Quiescent emitter current
+IC=IE //Quiescent collector current
+VO=vcc-(IC*RC) //Quiescent collector voltage
+
+re=1/(40*IE)
+av=-RC/re //voltage gain
+rp=(R1*R2)/(R1+R2)
+
+//if hfe=100
+hie1=hfe1*re
+ri1=(rp*hie1)/(rp+hie1)
+
+//if hfe=400
+hie2=hfe2*re
+ri2=(rp*hie2)/(rp+hie2)
+
+ro=RC
+
+//Results
+printf("Small Signal Voltage Gain = %d\n",av)
+printf("Small Signal Input Resistance is %d kOhm to %.1f kOhm\n",round(ri1/1000),(ri2/1000))
+printf("Small Signal Output Resistance is %.1f kOhm\n",(RC/1000))
+