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+//Book Name:Fundamentals of Electrical Engineering
+//Author:Rajendra Prasad
+//Publisher: PHI Learning Private Limited
+//Edition:Third ,2014
+
+//Ex5_10.sce.
+
+clc;
+clear;
+N=800;
+Hi=50e-3;
+Wi=40e-3;
+l_not=2e-3;
+A_not=2500e-6;
+leakage_factor=1.2;
+mew_not=4e-7*%pi;
+mew_r=322;
+pi_not=2.5e-3;
+lc=600e-3;                  //from the figure
+
+B_not=pi_not/A_not;
+H_not=B_not/mew_not;
+F_not=H_not*l_not;
+pi_T=pi_not*leakage_factor;
+Ac=Wi*Hi*0.92;                  //given 8 percent is taken for insulation . so (1-0.08=0.92)
+Bc=pi_T/Ac;
+Hc=Bc/(mew_r*mew_not);
+Fc=Hc*lc;
+F=Fc+F_not;
+Im=F/N;
+printf("\n Magnetizing current=%d A \n",Im)